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+ | </script></div><p> To illustrate the change taken by the decompose of signal molecule, we can see following simulation curves:</p><p> <img src='C:/Users/Dellll/Desktop/0-1.png' alt='1-10' /></p><p> X-axis refers to time. We find the efficiency will not be disturbed greatly at initial time, and will have a rapid decrease when the concentration equals to the half of origin. This property shows that we should control the reaction time otherwise the production will decay without production with the time going by. So the main purpose of this model is to predict when we dilute the input signal solution to obtain the maximum of protein to convert out signal.</p><p> We use matlab to obtain a rough curve of protein expression. X-axis refers to time. </p><p><img src='C:/Users/Dellll/Desktop/decay.png' alt='decay' /></p><p> This is a important result because it indicates that the production will not always increase with the time going. Actually, there exists a so-called "best time" to process next step in our system. For example, this peak can determine when we dilute input signal to get output signal as much as possible. </p><p><img src='C:/Users/Dellll/Desktop/%E5%90%88%E6%88%90%E9%85%B6.png' alt='合成酶' /></p><p> Red stars refers to "best time" according to different input concentration from upstream block.</p><p>*matlab code:</p><pre class="md-fences md-end-block" lang="matlab"> <div class="CodeMirror cm-s-inner CodeMirror-wrap"><div style="overflow: hidden; position: relative; width: 3px; height: 0px; top: 0px; left: 4px;"></div><div class="CodeMirror-scrollbar-filler" cm-not-content="true"></div><div class="CodeMirror-gutter-filler" cm-not-content="true"></div><div class="CodeMirror-scroll" tabindex="-1"><div class="CodeMirror-sizer" style="margin-left: 0px; margin-bottom: 0px; border-right-width: 30px; min-height: 322px; padding-right: 0px; padding-bottom: 0px;"><div style="position: relative; top: 0px;"><div class="CodeMirror-lines" role="presentation"><div role="presentation" style="position: relative; outline: none;"><div class="CodeMirror-measure"></div><div class="CodeMirror-measure"></div><div style="position: relative; z-index: 1;"></div><div class="CodeMirror-code" role="presentation"><div class="CodeMirror-activeline" style="position: relative;"><div class="CodeMirror-activeline-background CodeMirror-linebackground"></div><div class="CodeMirror-gutter-background CodeMirror-activeline-gutter" style="left: 0px; width: 0px;"></div><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-variable">n</span> = [];</span></pre></div><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-variable">fn</span> = [];</span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-keyword">for</span> <span class="cm-variable">i</span>=<span class="cm-number">1</span>:<span class="cm-variable">T</span><span class="cm-operator">/</span><span class="cm-variable">dt</span></span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-variable">n</span> = [<span class="cm-variable">n</span> <span class="cm-variable">i</span>];</span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-variable">t</span> = <span class="cm-builtin">exp</span>(<span class="cm-operator">-</span><span class="cm-variable">a</span><span class="cm-operator">*</span><span class="cm-variable">i</span><span class="cm-operator">*</span><span class="cm-variable">dt</span>);</span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-builtin">sum</span>=<span class="cm-number">0</span>;</span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-keyword">for</span> <span class="cm-variable">j</span>=<span class="cm-number">0</span>:<span class="cm-variable">i</span></span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-builtin">sum</span> = <span class="cm-builtin">sum</span> <span class="cm-operator">+</span> (<span class="cm-variable">Vm</span><span class="cm-operator">-</span>(<span class="cm-variable">j</span><span class="cm-operator">*</span><span class="cm-variable">dt</span>)<span class="cm-operator">^</span><span class="cm-variable">n</span>)<span class="cm-operator">*</span><span class="cm-builtin">exp</span>(<span class="cm-variable">a</span><span class="cm-operator">*</span><span class="cm-variable">dt</span><span class="cm-operator">*</span><span class="cm-variable">j</span>)<span class="cm-operator">*</span><span class="cm-variable">dt</span><span class="cm-operator">/</span>(<span class="cm-variable">k</span><span class="cm-operator">^</span><span class="cm-variable">n</span><span class="cm-operator">+</span>(<span class="cm-variable">Vm</span><span class="cm-operator">-</span>(<span class="cm-variable">dt</span><span class="cm-operator">*</span><span class="cm-variable">j</span>)<span class="cm-operator">^</span><span class="cm-variable">n</span>));</span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-keyword">end</span></span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-variable">y</span> = <span class="cm-variable">t</span><span class="cm-operator">*</span><span class="cm-builtin">sum</span><span class="cm-operator">+\</span><span class="cm-variable">phi</span><span class="cm-operator">*</span> (<span class="cm-variable">Vm</span> <span class="cm-operator">-</span> <span class="cm-variable">dt</span><span class="cm-operator">*</span><span class="cm-variable">i</span>)<span class="cm-operator">^</span>(<span class="cm-variable">n</span><span class="cm-number">-1</span>)<span class="cm-operator">/</span>(<span class="cm-variable">k</span><span class="cm-operator">^</span><span class="cm-variable">n</span> <span class="cm-operator">+</span> (<span class="cm-variable">Vm</span> <span class="cm-operator">-</span> <span class="cm-variable">dt</span><span class="cm-operator">*</span><span class="cm-variable">i</span>)<span class="cm-operator">^</span><span class="cm-variable">n</span>)<span class="cm-operator">^</span><span class="cm-number">2</span>;</span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-variable">fn</span> = [<span class="cm-variable">fn</span> <span class="cm-variable">y</span>];</span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-keyword">end</span></span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-builtin">plot</span>(<span class="cm-variable">n</span>,<span class="cm-variable">fn</span>);</span></pre><pre class=" CodeMirror-line " role="presentation"><span role="presentation" style="padding-right: 0.1px;"><span class="cm-builtin">max</span>(<span class="cm-variable">fn</span>);</span></pre></div></div></div></div></div><div style="position: absolute; height: 30px; width: 1px; border-bottom: 0px solid transparent; top: 322px;"></div><div class="CodeMirror-gutters" style="display: none; height: 352px;"></div></div></div></pre><p> This matlab code shows how we draw the curves and how to find maximum.</p><h2><a name='header-n115' class='md-header-anchor '></a>Model of parameter fitting and simulation</h2><h3><a name='header-n116' class='md-header-anchor '></a>Hill equation</h3><p> To get the parameter of Hill equation through our data, we tranfer Hill equation to following form:</p><div contenteditable="false" class="mathjax-block md-end-block" id="mathjax-n118" cid="n118" mdtype="math_block"><span class="MathJax_Preview"></span><span class="MathJax_SVG_Display" style="text-align: center;"><span class="MathJax_SVG" id="MathJax-Element-15-Frame" tabindex="-1" style="font-size: 100%; display: inline-block;"><svg xmlns:xlink="http://www.w3.org/1999/xlink" width="37.978ex" height="5.262ex" viewBox="0 -1409.3 16351.7 2265.7" role="img" focusable="false" style="vertical-align: -1.989ex;"><defs><path stroke-width="1" id="E16-MJMATHI-48" d="M228 637Q194 637 192 641Q191 643 191 649Q191 673 202 682Q204 683 219 683Q260 681 355 681Q389 681 418 681T463 682T483 682Q499 682 499 672Q499 670 497 658Q492 641 487 638H485Q483 638 480 638T473 638T464 637T455 637Q416 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+ | Hill\quad equation:y=V_{max}\times\frac{x^n}{k^n+x^n} |
Revision as of 05:10, 31 October 2017
Model
To illustrate the change taken by the decompose of signal molecule, we can see following simulation curves:
X-axis refers to time. We find the efficiency will not be disturbed greatly at initial time, and will have a rapid decrease when the concentration equals to the half of origin. This property shows that we should control the reaction time otherwise the production will decay without production with the time going by. So the main purpose of this model is to predict when we dilute the input signal solution to obtain the maximum of protein to convert out signal.
We use matlab to obtain a rough curve of protein expression. X-axis refers to time.
This is a important result because it indicates that the production will not always increase with the time going. Actually, there exists a so-called "best time" to process next step in our system. For example, this peak can determine when we dilute input signal to get output signal as much as possible.
Red stars refers to "best time" according to different input concentration from upstream block.
*matlab code:
n = [];
fn = [];
for i=1:T/dt
n = [n i];
t = exp(-a*i*dt);
sum=0;
for j=0:i
sum = sum + (Vm-(j*dt)^n)*exp(a*dt*j)*dt/(k^n+(Vm-(dt*j)^n));
end
y = t*sum+\phi* (Vm - dt*i)^(n-1)/(k^n + (Vm - dt*i)^n)^2;
fn = [fn y];
end
plot(n,fn);
max(fn);
This matlab code shows how we draw the curves and how to find maximum.
Model of parameter fitting and simulation
Hill equation
To get the parameter of Hill equation through our data, we tranfer Hill equation to following form: