Difference between revisions of "Team:TUDelft/Main-Test"

Line 6: Line 6:
  
 
<p> This is a $\frac12$ inline.</p>
 
<p> This is a $\frac12$ inline.</p>
−
$$\alpha = \frac{\left( 4\pi \right)^{3/2}}{12\pi}\sqrt{\frac{\lambda_{B}^{3}}{v}} $$<span align="right">(1)</span>
+
$$\alpha = \frac{\left( 4\pi \right)^{3/2}}{12\pi}\sqrt{\frac{\lambda_{B}^{3}}{v}} \tag{1}$$
−
$$a^2 = b^2 + c^2$$ <span align="right">(2)</span>
+
$$a^2 = b^2 + c^2$$ \tag{2}$$
 
   <--!        <p>
 
   <--!        <p>
 
                 This is some text $math\ \frac12$ other text $\unsupported$
 
                 This is some text $math\ \frac12$ other text $\unsupported$

Revision as of 12:35, 27 October 2017

This is a $\frac12$ inline.

$$\alpha = \frac{\left( 4\pi \right)^{3/2}}{12\pi}\sqrt{\frac{\lambda_{B}^{3}}{v}} \tag{1}$$ $$a^2 = b^2 + c^2$$ \tag{2}$$ <--!

This is some text $math\ \frac12$ other text $\unsupported$ Other node \[ displaymath \frac{1}{2} \] blah $$ \int_2^3 $$ and some Ξ more text \(and math\) blah. And $math with a \$ sign$.

Voor $V$ formule hier: $$\alpha = \frac{\left( 4\pi \right)^{3/2}}{12\pi}\sqrt{\frac{\lambda_{B}^{3}}{v}}$$

-->