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| When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are | | When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are |
| $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\leftrightarrow$$ | | $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\leftrightarrow$$ |
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| + | <p style="float: left;"><img src="https://static.igem.org/mediawiki/2017/5/55/T--Edinburgh_UG--adescr_excision.svg" height="200" width="200" border="1px"></p> |
| + | <p>Text Text Text Text Text Text Text Text Text Text Text Text Text Text Text Text Text Text Text</p> |
| + | </div> |
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| <body> | | <body> |
Revision as of 20:40, 1 November 2017
When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\leftrightarrow$$
![](https://static.igem.org/mediawiki/2017/5/55/T--Edinburgh_UG--adescr_excision.svg)
Text Text Text Text Text Text Text Text Text Text Text Text Text Text Text Text Text Text Text