Electromagnetic radiation is energy travelling as waves or photons. This is not the time or the place to go into this discussion [1] but Einstein and Infeld said it well:

Light, or the visible light spectrum range from \( \in [400 - 700] \) nm in the electromagnetic radiation spectrum. Above, with higher wavelengths, you will find infrared radiation (also known as IR), and under you will find the ultraviolet radiation (also known as UV). We call it visible light due to the fact that our eyes can only "pick up" these wavelengths. For this project we will mostly focus on light \( \lambda \in [470,520] \) nm region.

You have probably heard that nothing can travel faster than light? But not that many (non-physicist) remembers what velocity light actually travels with. In most cases it's enough to say that light travels in \( \sim 3.0 \cdot 10^{8}\) m/s in vacuum or \( \sim 6.7 {\cdot 10^{8}} \)mph.

The given wavelength \(\lambda \) for a lightsource can be found using the following formula:

\begin{align} \lambda = d sin(\theta) \end{align}

Where \(d\) is the grid spacing and \(\theta\) is the angle.

Continuing this part we will refer to light as waves. As shown in the picture above, visible light ranges around ∈[400−700] nm. This is known as the wavelength of the light, and to label it we use the symbol \(\lambda\). To better understand the physics we will start by using the rainbow as an example. Most people have had the pleasure to see this magnificent phenomenon in their life. To understand what happens to the light, we need to introduce the term refraction index. In short terms, this means that light will behave differently in different mediums if hit with an angle different than zero from the optical path. For air, the refraction index is simply \(1\), but for water it is \(1.33\), both in vacuum. Using Snell’s law and the fact that the light travels from air to water we can see that the angle with which the light will be emitted can be found by:

\begin{align} n_1 sin\theta_1 = n_2 sin\theta_2 \end{align}

The light from a light-emitting diode, LED for short, can be viewed by the human eye as monochromatic. This means it appears to only light up as one color. From theory we know that a LED cannot be monochromatic, thus proving one of the biggest differences between a LED and a laser. More importantly, the light from a LED is not coherent, meaning that the light waves do not have the same frequency. A LED loses little energy to heat as it applies most of its energy to light up the diode. This is a very useful property.

To create a simple LED-circuit you only need a couple of components: a LED, a resistance, some wires, a circuit board and a voltage source.

As one can see in the figure, our setup contains the following components: a LED-circuit as light source, lenses, two color filters, two mirrors, a spectrometer and a CCD-camera. The purpose of the lenses is to focus the light from the LED-circuit into a thin beam. This will make the LED-light more similar to a laser, and also increase the intensity of the light by concentrating it into a smaller radius. In order to make our light source act more like a laser, we need the light to have monochromatic properties. By using a blue color filter we can remove some of its spectrum, and obtain a correct wavelength for the GFP and yeast. It is worth mentioning that even though we use filters and lenses to focus the light, we still have to keep the LED at a maximum of 20V and hopefully the intensity is high enough for lasing to happen. Ideally, the mirrors we use should be 98% reflective and the last 2% should be emitted light that we can detect. We were not able to acquire mirrors of that sort, which is why our setup looks a bit different from that of a regular laser. The solution (both GFP or yeast) will be placed between the mirrors, in order to increase the effect of the light emitted from the solution. To be able to gather the light emitted from the GFP, which will be emitted in all directions, we place a big lense next to the mirror chamber. This lense will focus the light from the solution into a filter that removes the wavelengths that belongs to the LED, and by that we obtain the wavelengths we want to observe in a spectrometer or CCD-camera.